P(x)=60x-0.4x^2-3x+14

Solution for P(x)=60x-0.4x^2-3x+14 equation:

(P)=60P-0.4P^2-3P+14

We move all terms to the left:

(P)-(60P-0.4P^2-3P+14)=0

We get rid of parentheses

0.4P^2-60P+3P+P-14=0

We add all the numbers together, and all the variables

0.4P^2-56P-14=0

a = 0.4; b = -56; c = -14;
Δ = b2-4ac
Δ = -562-4·0.4·(-14)
Δ = 3158.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-\sqrt{3158.4}}{2*0.4}=\frac{56-\sqrt{3158.4}}{0.8}
$
$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+\sqrt{3158.4}}{2*0.4}=\frac{56+\sqrt{3158.4}}{0.8}
$